Please help me! I will give brainly!

Question,

Three pumpkins are catapulted at a contest. How much farther does Pumpkin C travel than Pumpkin A?

• Pumpkin A travels 0.61 mile.

• Pumpkin B travels 0.28 mile farther than Pumpkin A.

• Pumpkin B travels 0.06 mile farther than Pumpkin C.

How many Mile ____

Respuesta :

Answer:  0.34

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Explanation:

A = 0.61 is given to us

Pumpkin B travels 0.28 of a mile further than A does, so,

B = A+0.28 = 0.61+0.28 = 0.89

Pumpkin B travels 0.89 of a mile.

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Pumpkin C travels 0.06 of a mile more than B does, which means,

C = B + 0.06

C = 0.89 + 0.06

C = 0.95

Pumpkin C travels 0.95 of a mile.

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The last thing to do is to subtract the values of C and A

C - A = 0.95 - 0.61 = 0.34

Pumpkin C travels 0.34 of a mile further compared to pumpkin A.

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Side note: if you want to convert from miles to feet, then multiply by 5280.

For instance, 0.61 miles = 0.61*5280 = 3,220.8 feet.


If Pumpkin B travels 0.28 farther than A and 0.06 farther than be 0.28-0.06= 0.22 miles so the answer is 0.22 for pumpkin C