Answer:
The correct answer is "1020 K".
Explanation:
The given values:
[tex]n_{th} = 0,25[/tex]
[tex]n_2=0.50[/tex]
Now,
⇒ [tex]n_{th}(rev) = \frac{n_{th}}{n_2}[/tex]
By putting the values, we get
[tex]=\frac{0.25}{0.50}[/tex]
[tex]=0.50[/tex]
As we know,
⇒ [tex]n_{th} (rev)=1-\frac{TL}{TH}[/tex]
or,
⇒ [tex]TH=\frac{TL}{1-n_{th} (rev)}[/tex]
[tex]=\frac{510}{1-0.50}[/tex]
[tex]=\frac{510}{0.5}[/tex]
[tex]=1020 \ K[/tex]
