Answer:
[tex]v=10^5\ m/s[/tex]
Explanation:
Given that,
Magnetic force acting on an electron, [tex]F=12.8\times 10^{-19}\ N[/tex]
The magnitude of the magnetic field,[tex]B=8\times 10^{-5}\ T[/tex]
We need to find the magnitude of the velocity. We know that the magnetic force is given by :
[tex]F=qvB[/tex]
Where
v is the velocity
So,
[tex]v=\dfrac{F}{qB}\\\\v=\dfrac{12.8\times 10^{-19}}{1.6\times 10^{-19}\times 8\times 10^{-5}}\\\\v=10^5\ m/s[/tex]
So, the magnitude of velocity is[tex]10^5\ m/s[/tex].
