A tent maker wishes to support a 8-ft tent wall by attaching cable to the top of it, and then
anchoring the cable 7 feet from the base of the tent.
How long of a cable is needed?
Round your answer to the nearest tenth of a foot.
Answer with a numeric value only. That is, do not include "ft" or "feet" with your response.
Cable
Ground

Respuesta :

Answer:

10.6

Step-by-step explanation:

A simple sketch of the question would give a right angled triangle. So that we can easily apply the Pythagoras theorem to determine the length of the cable required.

Let the length of the cable required be represented by x.

[tex]/Hyp/^{2}[/tex] = [tex]/Adj 1/^{2}[/tex] + [tex]/Adj 2/^{2}[/tex]

[tex]x^{2}[/tex] = [tex]8^{2}[/tex] + [tex]7^{2}[/tex]

   = 64 + 49

[tex]x^{2}[/tex] = 113

x = [tex]\sqrt{113}[/tex]

  = 10.63

x = 10.6

The length of the cable required is 10.6 in feet.

The length of the cable needed to support the tenth wall is approximately 10.6 ft.

The situation forms a right angle triangle.

Right angle triangle:

Right angle triangle has one of it side as 90 degrees.

Therefore,

The tent wall is the opposite side of the triangle.

The table feet from the base of the tent is the adjacent side of the triangle.

Using Pythagoras's theorem the cable needed can be found.

Therefore,

  • c² = 8² + 7²

c² = 64 + 49

c = √113

c = 10.6301458127

length of the cable ≈ 10.6 feet

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