Respuesta :
Answer:
[tex]\displaystyle \frac{3x^8}{2}[/tex]
General Formulas and Concepts:
Algebra I
- Exponential Rule [Multiplying]: [tex]\displaystyle b^m \cdot b^n = b^{m + n}[/tex]
- Exponential Rule [Dividing]: [tex]\displaystyle \frac{b^m}{b^n} = b^{m - n}[/tex]
- Exponential Rule [Powering]: [tex]\displaystyle (b^m)^n = b^{m \cdot n}[/tex]
- Exponential Rule [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \frac{9x^{16}}{6(x^2)^3x^2}[/tex]
Step 2: Simplify
- Exponential Rule [Powering]: [tex]\displaystyle \frac{9x^{16}}{6x^6x^2}[/tex]
- Exponential Rule [Multiplying]: [tex]\displaystyle \frac{9x^{16}}{6x^8}[/tex]
- Exponential Rule [Dividing]: [tex]\displaystyle \frac{9x^8}{6}[/tex]
- Simplify: [tex]\displaystyle \frac{3x^8}{2}[/tex]