Answer:
0.620 rad/s
Explanation:
Given that:
diameter of the ring = 51.0 m
radius = diameter/2 = 51.0 m/2
= 25.5 m
In the system, the centripetal force is equal to the force as a result of the weight;
∴
mω²r = mg
ω²r = g
where:
ω = angular speed
[tex]\omega = \sqrt{\dfrac{g}{r}} \\ \\ \omega = \sqrt{\dfrac{9.8}{25.5}}[/tex]
ω = 0.620 rad/s
