What is this including the integers please?
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Answer:
3[tex]\sqrt{11}[/tex] + 2[tex]\sqrt{11}[/tex] = 5[tex]\sqrt{11}[/tex]
Step-by-step explanation:
[tex]\sqrt{99}[/tex] = [tex]\sqrt{(9)(11) }[/tex] = 3 [tex]\sqrt{11}[/tex] (separate perfect squares using factoring)
[tex]\sqrt{44}[/tex] = [tex]\sqrt{(4)(11)}[/tex] = 2 [tex]\sqrt{11}[/tex]
3 [tex]\sqrt{11}[/tex] + 2 [tex]\sqrt{11}[/tex] = 5 [tex]\sqrt{11}[/tex] (add like terms. Think of the [tex]\sqrt{11}[/tex] like x's.)
(Just add the coefficients)
Answer:
5[tex]\sqrt{11}[/tex]
Step-by-step explanation:
Using the rule of radicals
[tex]\sqrt{a}[/tex] × [tex]\sqrt{b[/tex] = [tex]\sqrt{ab}[/tex]
Simplifying the radicals
[tex]\sqrt{99}[/tex]
= [tex]\sqrt{9(11)}[/tex]
= [tex]\sqrt{9}[/tex] × [tex]\sqrt{11}[/tex]
= 3[tex]\sqrt{11}[/tex]
-----------------------
[tex]\sqrt{44}[/tex]
= [tex]\sqrt{4(11)}[/tex]
= [tex]\sqrt{4}[/tex] × [tex]\sqrt{11}[/tex]
= 2[tex]\sqrt{11}[/tex]
Then
[tex]\sqrt{99}[/tex] + [tex]\sqrt{44}[/tex]
= 3[tex]\sqrt{11}[/tex] + 2[tex]\sqrt{11}[/tex]
= 5[tex]\sqrt{11}[/tex]
with a = 5 and b = 11