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A local am radio station broadcasts at a wavelength of 349m, calculate the energy of the wavelength at which it is broadcasting?a. 5.69 x 10^-19 J b. 6.93 x 10^-39 J c. 8.59 x 10^5 J d. 6.33 x10^-45 J e. 7.71 x 10^-40 J

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jufsanabriasa

Answer:

E = 5.69x10⁻²⁸m

Explanation:

To solve this question we neeed to convert the wavelength in meters to energy in joules using the equation:

E = hc / λ

Where E is energy in joules, h is Planck's constant = 6.626x10⁻³⁴Js

c is light constant = 3.0x10⁸m/s

And λ is wavelength in meters = 349m

Replacing:

E = 6.626x10⁻³⁴Js*3.0x10⁸m/s / 349m

E = 5.69x10⁻²⁸m

Lanuel

The energy of the wavelength at which the local AM radio station is broadcasting is: A. [tex]5.69 \times 10^{-19}\;J[/tex]

Given the following data:

  • Wavelength = 349 nanometer = [tex]3.49 \times 10^{-7}\;meter[/tex]

Scientific data:

  • Speed of light = [tex]3 \times 10^8\;meters[/tex]
  • Planck constant = [tex]6.626 \times 10^{-34}\;J.s[/tex]

To calculate the energy of the wavelength at which the local AM radio station is broadcasting, we would apply Einstein's equation for photon energy:

Mathematically, Einstein's equation for photon energy is given by the formula:

[tex]E=\frac{hv}{\lambda}[/tex]

Where:

  • E is the energy.
  • h is Planck constant.
  • [tex]\lambda[/tex] is the wavelength.
  • v is the speed of light.

Substituting the given parameters into the formula, we have;

[tex]E=\frac{6.626 \times 10^{-34}\times 3 \times 10^8}{3.49 \times 10^{-7}}\\\\E=\frac{1.99 \times 10^{-25}}{3.49 \times 10^{-7}} \\\\E=5.69 \times 10^{-19}\;Joules[/tex]

Read more on wavelength here: https://brainly.com/question/14593563

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