Please help I learned this a while ago and forgot how to do it
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Answer:
The slope-intercept form is [tex]y=\frac{1}{2}x+\frac{11}{2}[/tex]
Step-by-step explanation:
To find the slope, use
[tex]m=\frac{y^2-y^1}{x^2-x^1}[/tex]
Replace the x and y values with the points.
[tex]m=\frac{7-5}{3-(-1)}[/tex]
Solve.
[tex]m=\frac{2}{4}[/tex]
[tex]m=\frac{1}{2}[/tex]
After that, find the y-intercept form.
Put the equation in point-slope form.
[tex]y-5=\frac{1}{2}(x+1)[/tex]
Replace x with 0.
[tex]y-5=\frac{1}{2}(0+1)[/tex]
[tex]y-5=\frac{1}{2}[/tex]
Add 5 to both sides.
[tex]y=5\frac{1}{2}[/tex]
Convert to improper fraction form.
The y-intercept is [tex]\frac{11}{2}[/tex]
Now finally, write in slope-intercept form. (y=mx+b)
m is slope, b is the y-intercept.