I don't think that there is enough info for this problem, but could someone try to help?
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Answer:
12
Step-by-step explanation:
Rectangle : Let length = b & width = a
PQ = QR = 6
LR = QR - PL = 6 - a
ΔPQR ~ ΔMLR
In similar triangles, corresponding sides are in same ratio.
[tex]\frac{PQ}{QR}=\frac{ML}{LR}\\\\\frac{6}{6}=\frac{a}{6-b}[/tex]
[tex]1 =\frac{a}{6-b}[/tex]
6 - b = a
6 = a + b
a +b = 6
Perimeter of rectangle = 2*(length +width}
= 2*(a+ b)
= 2 * 6
= 12