Given:
The function is:
[tex]f(x)=\sqrt{x-3}[/tex]
To find:
The inequality that is used to find the domain of the given function.
Solution:
We have,
[tex]f(x)=\sqrt{x-3}[/tex]
We know that the radical functions are defined for only positive values of radicand.
It means the given function is defined if the value of (x-3) is greater than or equal to 0.
[tex]x-3\geq 0[/tex]
Adding 3 on both sides, we get
[tex]x-3+3\geq 0+3[/tex]
[tex]x\geq 3[/tex]
The inequality [tex]x-3\geq 0[/tex] is used to find the domain of the given function and the domain of the given function is [tex]x\geq 3[/tex].
Therefore, the correct option is B.
