Answer:
The rock hits the ground between 2 seconds and 2.5 seconds after it is dropped
Step-by-step explanation:
The given table is presented as follows;
[tex]\begin{array}{ccl}t&h(t)&Description\\0&20&Initial \ height\\0.5&18.8&Rock \ in \ downward \ motion\\1&15.1&\\1.5&9&\\2&0.4&The \ height \ just \ before \ the \ rock \ hits \ the \ ground \\2.5&-10.6&The \ calculated \ height \ after\ the \ rock \ hits \ the \ ground \\3&-24.1&Calculated \ height \ after\ the \ rock \ hits \ the \ ground\end{array}[/tex]
Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.
