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A gas cylinder contains argon atoms (m = 40.0 u). The temperature is increased from 293 K (20◦C) to 373 K (100◦C).(a) What is the change in the average kinetic energy per atom? *

Respuesta :

Answer:

1.656 × 10^(-21) J

Explanation:

Formula for the average translational kinetic energy per atom is;

K.E = (3/2)kΔt

Where;

k is boltzmann constant = 1.38 × 10^(-23) J/K

ΔT is change in temperature = 373 - 293 = 80 K

Thus;

K.E = (3/2) × 1.38 × 10^(-23) × 80

K.E = 1.656 × 10^(-21) J