Respuesta :

Answer:

The distance is 7[tex]\sqrt{2}[/tex]

Step-by-step explanation:

Ver imagen rajavamsi566

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{The formula for \underline{distance between} is: }\mathsf{\sqrt{(x_2-x_1)^2 + (y_2 - y_1)^2}}[/tex]

[tex]\large\textsf{Whereas }\mathsf{x_2}\large\textsf{ is }\mathsf{2}\large\textsf{ and }\mathsf{x_1}\large\textsf{ is }\mathsf{ -5}\\\\\large\textsf{And also }\mathsf{y_2}\large\textsf{ is }\mathsf{ -2}\large\textsf{ and }\mathsf{ y_1}\large\textsf{ is }\mathsf{5}[/tex]

[tex]\mathsf{\sqrt{(2 - -5)^2+ (-2 + 5)^2}}\\\mathsf{2 - -5}\\\mathsf{= 2 + 5}\\\mathsf{= \bf 7}\\\\\mathsf{-2 + 5}\\\mathsf{= \bf -7}\\\\\mathsf{= \sqrt{(7)^2+ (-7)^2}}\\\\\mathsf{7^2}\\\mathsf{= 7\times7}\\\mathsf{= \bf 49}\\\\\mathsf{(-7)^2}\\\mathsf{= -7\times-7}\\\mathsf{= \bf 49}\\\\\mathsf{= \sqrt{49 +49}}\\\\\mathsf{49+49}\\\mathsf{=\bf 98}[/tex]

[tex]\mathsf{= \sqrt{98}}\\\mathsf{= 7\sqrt{2}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf 7\sqrt{2}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]