the longest side of a triangle is 80cm more than the second and 130cm more than the shortest side and its perimeter is 540cm. find its area

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Answer:

Area of triangle1/2b*h Now you can do

The area of the triangle is 9000 square centimeters

How to determine the area?

Let the sides in order of length be represented as:

x, y and z.

So, we have:

z = 80 + y

z = 130 + x

P = 540

The perimeter is calculated as:

P = x + y + z

So, we have:

x + y + z =540

Substitute z = 130 + x

x + y + 130 + x =540

Evaluate the like terms

2x + y = 410

Substitute z = 130 + x in z = 80 + y

130 + x  = 80 + y

Evaluate the like terms

x - y = -50

So, we have:

2x + y = 410

x - y = -50

Add both equations

3x = 360

Divide by 3

x = 120

Substitute x = 120 in z = 130 + x

z = 130 + 120

z = 250

Substitute z = 250 in z = 80 + y

250 = 80 + y

y = 170

So, we have:

x = 120

y = 170

z = 250

The area is then calculated as:

[tex]Area = \sqrt{s * (s -x) *(s - y) * (s -z)[/tex]

Where

s = P/2 = 540/2

s = 270

So, we have:

[tex]Area = \sqrt{270 * (270 -120) *(270 - 170) * (270 -250)[/tex]

Evaluate

Area = 9000

Hence, the area of the triangle is 9000 square centimeters

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