Answer:
[tex] {x}^{2} −7x+12[/tex]
Step-by-step explanation:
[tex](x−3)(x−4)[/tex]
[tex]x(x−4)−3(x−4)[/tex]
[tex]x \times x+x(−4)−3x−3(−4)[/tex]
[tex] {x}^{2} −4x−3x+12[/tex]
x
[tex] {x}^{2} - 7x + 12[/tex]
[tex](x - 3)(x - 4)[/tex]
[tex]x( x - 4) - 3(x - 4)[/tex]
[tex] {x}^{2} - 4x - 3x + 12[/tex]
