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A chemical reaction was carried out by mixing 25 g of pure CaCO3 and 0.75 mole of pure HCl to give CaCl2, H2O and CO2. a. Which one is the limiting reactant and why? b. Calculate the mass of CaCl2 produced. c. How many number of water molecules are formed? d. Calculate the volume of CO2 gas liberated at STP. e. What mass of NaOH is required to absorb the whole CO2 produced in the reaction?​

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All the options are solved and answer is written below

What is a Chemical Reaction ?

A reaction between two or more compounds to form products made after chemical change is called a chemical reaction.

It is given that

A chemical reaction was carried out by mixing 25 g of pure CaCO₃ and 0.75 mole of pure HCl

CaCl₂ , H₂O and CO₂  are the products obtained.

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

Mole ratio CaCO₃ : HCl : CaCl₂ : H₂O = 1 : 2 : 1 : 1

Molar mass of CaCO₃  = 100 g/mol

Molar mass of HCl  = 36.5 g/mol

Molar mass of H₂O = 18 g/mol

Molar mass of CaCl₂= 110.98 g/mol

Moles of CaCO₃ = 25/100 = 0.25 moles

Moles of HCl present = 0.75 mole

For 0.25 moles of CaCO₃ 0.5 moles of HCl is required , as the moles of HCl is present in excess therefore

a. CaCO₃ is the limiting reactant

b. mass of CaCl₂ produced

Moles of CaCl₂  produced = 0.25 moles

1 mole means 110.98 gm

0.25 mole means 0.25* 110.98 = 27.74 gm

c. moles of water molecules formed

for 0.25 moles of CaCO₃ 0.25 moles of water will be formed

d.Volume of Co produced at STP

PV = nRT

P= 1 atm

V=?

R = 0.0821 atm L/K/mol

V = 0.25 * 0.0821 * 273 /1

V = 5.6 liter

e. The mass of NaOH required to absorb CO₂ produced in the reaction

Ratio of NaOH:CO₂ = 2 :1

0.5 moles will be required , i.e.

0.5 *40

20 grams of NaOH will be required.

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