Please help me to solve this question pleaseee
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Answer:
Step-by-step explanation:
1) ML // JK , MK is transversal,
∠LMK = ∠MKJ {Alternate interior angles are congruent}
∠LMK = 30°
In ΔMKO,
30 + 115 + ∠ JLM = 180 {Angle sum property of triangle}
145 +∠ JLM = 180
∠ JLM = 180 - 145
∠ JLM = 35°
2) AB // CD , AC is transversal
∠DCA = ∠BAC {Alternate interior angles are congruent}
∠DCA = 23
∠BCD = ∠DCA + ∠BCA
= 23 + 37
= 60
3) EF // HG ; FH is transversal
∠FHG = ∠HFE {Alternate interior angles are congruent}
∠FHG = 77
4) ZY // WX ; WY is transversal
∠ZYW = ∠XWY {Alternate interior angles are congruent}
= 65
ZY // WX ; WY is transversal
∠ZWY = ∠WYX {Alternate interior angles are congruent}
= 36
In ΔWZY
36 + 65 + ∠z = 180
101 +∠Z = 180
∠Z = 180 - 101
∠Z = 79