Respuesta :
To determine the force per meter of a light bolt at the equator that carries 20 000 A and is perpendicular to the Earth's magnetic field with a magnitude of 3x10-5 T, we do this:
20000 / 3x10-5 = 666.67x10^6 N/m
The direction of the force would be to the left parallel to the equator.
20000 / 3x10-5 = 666.67x10^6 N/m
The direction of the force would be to the left parallel to the equator.
Answer:
667.6 × 10⁶ Nm
Explanation:
To determine the force, let:
The force be = 20 000 A
The magnetic field = 3 × 10⁻⁵
Thus, the force will be = [tex]\frac{20000}{3*10^{5} } \\ = 666.67 * 10^{6} N m[/tex]
Thus, the direction will be parallel to the equator