Answer: D) the iconic compound calcium fluoride (CaF₂)
Explanation:
[tex]\Delta T_f=i\times k_f\times m[/tex]
where,
[tex]\DeltaT_f[/tex] = change in freezing point
i= vant hoff factor
[tex]k_f[/tex] = freezing point constant
m = molality
A) the molecular compound sucrose (C₁₂H₂₂O₁₁)
: For non electrolytes like sucrose, vant hoff factor is 1.
B) the iconic compound magnesium sulfate (MgSO₄): For electrolytes, vant hoff factor is equal to the number of ions it produce on dissociation.
[tex]MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}[/tex] Thus i= 2
C) the iconic lithium chloride (LiCI):
[tex]LiCl\rightarrow Li^++Cl^-[/tex], thus i=2.
Thus 1% produces most ions and thus lowers the freezing point to maximum.
D) the iconic compound calcium fluoride(CaF₂):
[tex]CaF_2\rightarrow Ca^{2+}+2F^-[/tex], thus i=3.
Thus the compound with highest value of i, will depress the freezing point to maximum.
Answer:
D) the iconic compound calcium fluoride (CaF₂)
Explanation:
I took the test and got it right
