Dalexnoe7las
contestada

To rent a certain meeting room, a college charges a reservation fee of $42 and an additional fee of $7.70 per hour. The math club wants to spend less than $80.50 on renting the meeting room.
What are the possible amounts of time for which they could rent the meeting room?
Use t for the number of hours the meeting room is rented, and solve your inequality for t .

Respuesta :

$42+7.70(t)=$80.50
Subtract 42

7.70t=38.50
Divide by 7.70

t=5 hours
JcAlmighty
The answer is t < 5 hours

t - the number of hours

An additional fee of $7.70 per hour is 7.70t
The math club wants to spend less than $80.50: < 80.50 

Hence:
42 +7.70t < 80.50
7.70t < 80.50 - 42
7.70t < 38.5
t < 38.5 : 7.70
t < 5 hours

Otras preguntas