Respuesta :
Centripetal acceleration = (speed)²/(radius) .
We know the radius. We have to find the speed.
Speed around a circle = (circumference) / (time to go around)
The circumference of the circle is (2 π) (radius) = 4 π meters.
We don't exactly know the time to go around.
We know that the ball goes around 0.7 times/second.
Flip that over, and you have time to go around = second/0.7 .
So now, the centripetal acceleration is
(speed)²/(radius) .
= (4π meters · 0.7/sec)² / (2 meters)
= (4π · 0.7 / 2) m/s²
= about 4.4 m/s²
We know the radius. We have to find the speed.
Speed around a circle = (circumference) / (time to go around)
The circumference of the circle is (2 π) (radius) = 4 π meters.
We don't exactly know the time to go around.
We know that the ball goes around 0.7 times/second.
Flip that over, and you have time to go around = second/0.7 .
So now, the centripetal acceleration is
(speed)²/(radius) .
= (4π meters · 0.7/sec)² / (2 meters)
= (4π · 0.7 / 2) m/s²
= about 4.4 m/s²
The centripetal acceleration of the ball will be 38.68 meter per sq.second.
What is centripetal acceleration?
The acceleration needed to move a body in a curved way is understood as centripetal acceleration.
The direction of centripetal acceleration is always in the path of the center of the course.
The given data in the problem;
r is the radius= 2.00m
frequency (f) = 0.7 rev/s
The angular velocity is found as;
[tex]\rm \omega = 2 \pi f \\\\ \omega = 2 \times 3.14 \times 0.7 \\\\ \omega = 4.398 \ rad/sec[/tex]
The centripetal acceleration is given by;
[tex]\rm a_c= \omega^2r \\\\\ a_c= (4.398)^2 \times 2.00 \\\\ a_c=38.68 \ m/sec^2[/tex]
Hence, the centripetal acceleration of the ball will be 38.68 meter per sq.second.
To learn more about the centripetal acceleration refer to the link;
https://brainly.com/question/17689540
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