in DEF DE=17 m angle =32 Find DF nearest tenth
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Answer:
(A) 32.1
Step-by-step explanation:
It is given that in ΔDEF, DE=17 and m∠F=32, thus
Using the trigonometry, we have
[tex]sinx=\frac{Perpendicular}{Hypotenuse}=\frac{DE}{DF}[/tex]
⇒[tex]sin32^{\circ}=\frac{17}{DF}[/tex]
⇒[tex]DF=\frac{17}{sin32^{\circ}}[/tex]
⇒[tex]DF=\frac{17}{0.529}[/tex]
⇒[tex]DF=32.1[/tex]
Therefore, the value of DF is 32.1.
Hence option A is correct.