Respuesta :
If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by yes, by AA similarity criterion
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Answer:
Option A is correct.
Yes, by AA similarity criterion
Step-by-step explanation:
AA(Angle-Angle) Similarity Criterion states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.
In ΔBAC and ΔCED
[tex]\angle BAC = \angle CED = 17^{\circ}[/tex] [Angle] [Given]
[tex]\angle C = \angle C[/tex] [Angle] [Common angle]
Therefore, by AA similarity criterion;
[tex]\triangle BAC \sim \triangle CED[/tex]
Therefore, ΔBAC and ΔCED are similar by AA similarity criterion.
