Answer:
Step-by-step explanation:
We know that the distance traveled is
[tex]d=2000ft[/tex]
The time that took to travel this distance is
[tex]t<10min[/tex]
This means that the time could be 9 minutes, 8 minutes, 7 minutes. It can be a number between 0 and 10.
The speed is defined as
[tex]s=\frac{d}{t}[/tex]
Replacing all values, we have
[tex]s=\frac{2000ft}{10min}= 200 ft/min[/tex]
Therefore, the speed can be expressed like less than 200 feet per minutes.
Another possible example is using a time of 9 minutes
[tex]s=\frac{2000ft}{9min}= 222.22 ft/min[/tex]
In this case, the speed would be 222.22 feet per minute or less. Notice that this time the speed is not "less than", we have to include a equality relation, because we already used a time that's inside the interval of time given by the problem.
