Answer:
3.01 × 10²³ atoms Ne
General Formulas and Concepts:
Atomic Structure
- Reading a Periodic Tables
- Moles
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
Identify
[Given] 10.1 g Ne
[Solve] atoms Ne
Step 2: Identify Conversions
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
[PT] Molar Mass of Ne: 20.18 g/mol\
Step 3: Convert
- [DA] Set up: [tex]\displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})[/tex]
- [DA] Divide/Multiply [Cancel out units]: [tex]\displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne
