Answer: hello your question lacks vital data hence I will provide you with a general equation within the scope of your question
answer :
General equation = ( Stiver and Mackay or EPA ) evaporation equations
E = [tex]\frac{PAW}{T +459.67}[/tex] or E = [tex]\frac{7.4PA(0.447W)^{0.8} }{T + 459.67}[/tex]
Step-by-step explanation:
Given data
volume of water in pool = 0.9 i.e. 90% full
rate of evaporation = 7.5ft^3 per day = 56.1039 gallons / day
Assumption :
Volume of pool = 16,000 gallons
In order to resolve the missing part of the problem apply the equation below
E = [tex]\frac{PAW}{T +459.67}[/tex] or E = [tex]\frac{7.4PA(0.447W)^{0.8} }{T + 459.67}[/tex]
where : E = Evaporation rate , P = water's vapor pressure , A = pool surface Area , W = wind speed , T = Temperature in Fahrenheit
