Answer:
The division will be represented as:
[tex]\frac{18x^{2}-3x+4}{6x+5}=(3x-3)+\frac{19}{6x+5}[/tex]
Step-by-step explanation:
1) Let's find a number with a variable that multiplied by 6x gives as 18x². It will be 3x, because (6x+5)3x=18x²+15x.
Now, let's subtstract:
[tex](18x^{2}-3x+4)-(18x^{2}+15x)=-18x+4[/tex]
2) Let's find a number with a variable that multiplied by 6x gives as -18x. It will be -3, because (6x+5)(-3)=-18x-15.
Now, let's subtstract:
[tex](-18x+4)-(-18x-15)=19[/tex]
Therefore, the division will be represented as:
[tex]\frac{18x^{2}-3x+4}{6x+5}=(3x-3)+\frac{19}{6x+5}[/tex]
I hope it helps you!
