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FORCE AND DISPLACEMENT AT AN ANGLE A sailor pulls a boat a distance of 30.0 m along a dock using a rope that makes a 25.0° angle with the horizontal. How much work does the rope do on the boat if its tension is 255 N?​

Respuesta :

Answer: 6117.58 J

Explanation:

We know that W=Fd*cos(theta) where theta is the angle between the displacement and the force.

In this case, we are given that F=225 N, d=30 m, and theta=25 degrees.

Plugging all this in we get

W=225*30*cos(25)=6117.58 J

Work done by the rope when sailor pulls the boat in the dock is 6930.9 J

What is work ?

The work is defined by the product of force and displacement. Its standard formula is,

[tex]W = F.d.Cos\alpha[/tex]

Here F is force, d is displacement and α is angle subtended by force from horizontal.

  • As given in the question,

      F = 255N, d = 30m, α = 30°

  • On putting in the above formula

      W = 255×30×Cos30°  

           =7650×0.906

           = 6930.9 J

To learn more about work here

https://brainly.com/question/4095205

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