Respuesta :

wegnerkolmp2741o

Answer:

sqrt( 17^2+ 25^2)

Step-by-step explanation:

Since this is a right triangle, we can use Pythagorean theorem

a^2+b^2 = c^2  where a and b are the sides and c is the hypotenuse

Taking the square root of each side

sqrt(a^2+b^2) = QR

sqrt( 17^2+ 25^2) = QR

Answer:

[tex] \small \sf A. \sqrt{25 {}^{2} + 17 {}^{2} } [/tex]

Step-by-step explanation:

Using pythagoras theorem

( Base) ² + ( Perpendicular) ² = (Hypotenuse) ²

( QS)² + ( RS)² = (OR )²

( 25 )² + ( 5 )² = OR²

Taking square root of each side.

[tex] \sqrt{25 {}^{2} + 17 {}^{2} } = \sqrt{OR}[/tex]

[tex] \sqrt{25 {}^{2} + 17 {}^{2} } = {OR}[/tex]

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