The equation of a linear function in point-slope form is y-y1=m(x-x1). Harold correctly wrote the equation y=3(x-7) using a point and the slope. Which point did Harold use ?
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Answer:
(7, 0).
Step-by-step explanation:
We have y = 3(x - 7)
y = 3x - 21
Point-slope form is
y - y1 = 3(x - x1)
y - y1 = 3x - 3x1
Comparing this to the equation y = 4x - 21 we see that y1 = 0 and x1 = 7.