Respuesta :
Answer:
Incomplete question, but you use the normal distribution to solve it, with [tex]\mu = 23.5[/tex] and [tex]\sigma = 3.6[/tex]
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The average waiting time to be seated for dinner at a popular restaurant is 23.5 minutes, with a standard deviation of 3.6 minutes.
This means that [tex]\mu = 23.5, \sigma = 3.6[/tex]
Thus
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{X - 23.5}{3.6}[/tex]
Find the probability that the patron will have to wait:
More than X minutes:
1 subtracted by the p-value of Z
Between A and B minutes:
p-value of Z when X = A subtracted by the p-value of Z when Z = B.
Less than X minutes.
p-value of Z.
