darkn3ss909
contestada

4. A 268 kg boulder rolls down a hill. If it had 50,000 J of energy to start with, how high was the hill? (Can anyone explain or give the equation for it? Thank you!)​

Respuesta :

Answer:

h = 18.65 m

Explanation:

Given that,

The mass of a boulder, m = 268 kg

The potential energy at the hill, E = 50,000 J

We need to find the height of the hill.

We know that, the potential energy of an object is given by :

E = mgh

Where

h is the height of the hill

So,

[tex]h=\dfrac{E}{mg}\\\\h=\dfrac{50000}{268\times 10}\\\\h=18.65\ m[/tex]

So, the height of the hill is 18.65 m.
  • Mass=268kg=m
  • P.E=50000J
  • acceleration due to gravity=g=10m/s^2
  • Height be h

[tex]\\ \sf\longmapsto PE=mgh[/tex]

[tex]\\ \sf\longmapsto 50000=268(10)h[/tex]

[tex]\\ \sf\longmapsto 50000=2680h[/tex]

[tex]\\ \sf\longmapsto h=\dfrac{50000}{2680}[/tex]

[tex]\\ \sf\longmapsto h=18.65m[/tex]

Otras preguntas