The third term of the given sequence exists 19.
Term to term rule when the sequence [tex]$-2,1,19 \ldots .$[/tex] is reversed will be [tex]$\frac{a-13}{6}$[/tex].
What is a sequence?
The sequence exists in a particular order in which connected things follow each other.
The term-to-term rule of the sequence stands 6a+13, where a stands for the first term First-term a = -2
Second term b will be [tex]$-2*6+13=1$[/tex]
The rule for the third term will be 6b+13, where b will be the second term. So the third term will be [tex]$6* 1+13=19$[/tex]
So, the sequence will be [tex]$-2,1,19 \ldots \ldots . .$[/tex]
If the order of the above sequence stands reversed, the new sequence will be [tex]$19,1,-2 \ldots \ldots .$[/tex]
If we subtract 13 from first term 19 and then divide by 6 we will get 1 which stands for the second term of the new sequence [tex]$19,1,-2 \ldots \ldots .$[/tex]
So a new term-to-term sequence rule will be [tex]$\frac{a-13}{6}$[/tex] where a stands for the first term.
Therefore, the third term of the given sequence exists 19.
Term to term rule when the sequence [tex]$-2,1,19 \ldots .$[/tex] exists reversed will be [tex]$\frac{a-13}{6}$[/tex].
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