A stock solution of calcium sulfate, CaSO4 has a concentration of 3.00 M. The volume of this solution is 150 mL. What volume of a 1.25 M solution could be made from the stock solution?

Respuesta :

Answer: The volume of stock solution needed is 62.5 mL

Explanation:

A solution consists of solute and solvent. A solute is defined as the component that is present in a smaller proportion while the solvent is defined as the component that is present in a larger proportion.

To calculate the volume of stock solution needed, the formula used is:

[tex]C_1V_1=C_2V_2[/tex]             ....(1)

where,

[tex]C_1\text{ and }V_1[/tex] are the concentration and volume of stock solution.

[tex]C_2\text{ and }V_2[/tex] are the concentration and volume of diluted solution.

We are given:

[tex]C_1=3.00M\\V_1=?mL\\C_2=1.25M\\V_2=150mL[/tex]

Putting values in equation 1, we get:

[tex]3.00\times V_1=1.25\times 150\\\\V_1=\frac{1.25\times 150}{3.00}\\\\V_1=62.5mL[/tex]

Hence, the volume of stock solution needed is 62.5 mL