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You lift a 10-N physics book up in the air a distance of 1.0 m, at a constant velocity
of 0.50 m/s. What is the work done by gravity on the book?
1) +10 J
2) -10
3) +5.0
4) -5.0

Respuesta :

The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

F = mg = (10 N) (9.80 m/s^2) = 9.8 N ≈ 10 N

You raise the book 1.0 m in the opposite direction, so the work done is

W = (10 N) (-1.0 m) = -10 J

The work done by gravity on the book is -10 Joules. The correct option is 2.

What is gravity?

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.

Given are the three positions. The Earth has the acceleration due to gravity, g =  9.81 m/s²,

The book is lifted upward, but gravity points down, so the work done by gravity must be negative (so you can eliminate options 1 and 3).

The force exerted on the book by gravity has magnitude

F = mg = 10 N x( -9.80 m/s² )= -9.8 N

F ≈ -10 N

The book is raised by  1.0 m in the opposite direction, so the work done is

W =- 10 N x 1.0 m = -10 J

Thus, the correct option is 2.

Learn more about gravity.

brainly.com/question/4014727

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