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The chemical equation of rusting of iron is given
Fe + O2 → 2Fe2O3
a) Write the reactants and products in this reaction
b) Write the total number of reactant atoms
c) Can you balance the above equation?

Respuesta :

Answer:

[tex]{ \tt{(a). { \bf{reactants : { \tt{iron \: and \: oxygen}}}}}} \\ { \bf{products : { \tt{iron(iii)oxide}}}} \\ \\ { \tt{(b).}} \: { \bf{1.204 \times {10}^{24} \: atoms}} \\ { \tt{(c).}} \: { \tt{4Fe +3 O _{2} → 2Fe _{2}O _{3}}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]