Answer:
Step-by-step explanation:
Thank your for revising and improving the image.
Assuming DF is a straight line,
Given E is the mid-point of DF
mCE = mGF
CE || GF
Then
mDE = mEF (E midpoint of DF)
Angle DEC = Angle EFG (corresponding angle, DF transversal of parallel lines CE and GF)
mCE = mGF (given)
Then triangles DCE and EGF are congruent by reason SAS (side-angle-side)
