The second partial sum for [tex]\sum\limit^\infty_{n=1}\; 3* (\frac{1}{2})^{n-1}[/tex] is [tex]3* (\frac{1}{2})^0 + 3* (\frac{1}{2})^1[/tex]
The correct option is (1)
What is Summation ?
A summation, also called a sum, is the result of arithmetically adding numbers or quantities. A summation always contains a whole number of terms.
The given summation is:
[tex]\sum\limit^\infty_{n=1}\; 3* (\frac{1}{2})^{n-1}[/tex]
If we put two values of n i.e., n=1,2. hen we get the following summation series
=[tex]3* (\frac{1}{2})^{1-1} + 3* (\frac{1}{2})^{2-1}[/tex]
=[tex]3* (\frac{1}{2})^0 + 3* (\frac{1}{2})^1[/tex]
The option answer matches with the option 1.
Hence the correct option is (1)
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