Answer:
[tex]L =21.945[/tex] --- Length
[tex]W = 7.9725[/tex] --- Width
Step-by-step explanation:
Given
Let
[tex]L \to Length[/tex]
[tex]W \to Width[/tex]
So:
[tex]Area = 175[/tex]
[tex]L = 6 + 2W[/tex]
Required
The dimension of the rectangle
The area is calculated as:
[tex]Area =L*W[/tex]
This gives:
[tex]175 =L*W[/tex]
Substitute: [tex]L = 6 + 2W[/tex]
[tex]175 =(6 + 2W)*W[/tex]
Open bracket
[tex]175 =6W + 2W^2[/tex]
Rewrite as:
[tex]2W^2+ 6W -175 = 0[/tex]
Using quadratic formula:
[tex]W = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]
This gives:
[tex]W = \frac{-6 \± \sqrt{6^2 - 4*2*-175}}{2*2}[/tex]
[tex]W = \frac{-6 \± \sqrt{1436}}{2*2}[/tex]
[tex]W = \frac{-6 \± 37.89}{4}[/tex]
Split
[tex]W = \frac{-6+ 37.89}{4}, W = \frac{-6- 37.89}{4}[/tex]
[tex]W = \frac{31.89}{4}, W = \frac{-43.89}{4}[/tex]
The width cannot be negative;
So:
[tex]W = \frac{31.89}{4}[/tex]
[tex]W = 7.9725[/tex]
Recall that:
[tex]L = 6 + 2W[/tex]
[tex]L =6 + 2 * 7.9725[/tex]
[tex]L =21.945[/tex]
