Answer: The equilibrium constant for the reverse reaction at the same temperature is [tex]2.40 \times 10^{33}[/tex].
Explanation:
The given reaction equation is as follows.
[tex]2HCl(g) \rightleftharpoons H_{2}(g) + Cl_{2}(g)[/tex] ... (1)
It's equilibrium constant (K) value is [tex]4.17 \times 10^{-34}[/tex].
Also, another reaction equation is as follows.
[tex]H_{2}(g) + Cl_{2}(g) \rightleftharpoons 2HCl(g)[/tex]
This is the reverse of equation (1). Hence, its equilibrium value is calculated as follows.
[tex]K' = \frac{1}{K}\\= \frac{1}{4.17 \times 10^{-34}}\\= 2.40 \times 10^{33}[/tex]
Thus, we can conclude that the equilibrium constant for the reverse reaction at the same temperature is [tex]2.40 \times 10^{33}[/tex].
