The values of A, B, C and D are (d) A = 1, B = 0, C = 3 and D = -3
How to solve for A, B, C and D?
From the question, we have:
x^3 + 8x - 3 = Ax^3 + 5Ax + Bx^2 + 5B + Cx + D
Collect like terms
x^3 + 8x - 3 = Ax^3 + Bx^2 + 5Ax + Cx + 5B + D
By comparing the coefficients, we have:
Ax^3 = x^3
Bx^2 = 0
5Ax + Cx = 8x
5B + D = -3
Remove the x factors
A = 1
B = 0
5A + C = 8
5B + D = -3
Substitute A = 1 in 5A + C = 8
5(1) + C = 8
Solve for C
C = 3
Substitute B = 0 in 5B + D = -3
5(0) + D = -3
Solve for B
D = -3
Hence, the values of A, B, C and D are (d) A = 1, B = 0, C = 3 and D = -3
Read more about partial fractions at:https://brainly.com/question/18958301
#SPJ6
