Which function is positive for the entire interval [–3, –2]?

On a coordinate plane, a curved line with a minimum value of (0, negative 3) crosses the x-axis at (negative 3, 0) and (3, 0), and crosses the y-axis at (0, negative 3).

On a coordinate plane, a curved line with a minimum value of (2, negative 3) crosses the x-axis at (negative 1, 0) and (5, 0), and crosses the y-axis at (0, negative 1.5).

On a coordinate plane, a curved line with a minimum value of (2, 4) and a maximum value of (0.5, 6), crosses the x-axis at (negative 1.5, 0) and crosses the y-axis at (0, 5).

On a coordinate plane, a curved line with a minimum value of (negative 1.75, negative 3.9) and a maximum value of (0, 2), crosses the x-axis at (negative 2.2, 0), (negative 0.75, 0), and (0.75, 0), and crosses the y-axis at (0, 2).

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Answer:

Graph (B) represents that the  function is positive for the entire interval [-3, -2]

Step-by-step explanation:

According to the question,

  • We are given four different graphs for different functions, We need to find the function graph which is positive of the entire interval [-3, -2] . It is a closed interval. So it is inclusive of -3 and -2.
  • In this interval, the graph of the Y value must be in a positive region. So we Have To Determine A Function That Is Positive For The Entire Interval [-3 , -2].  

By looking at the graph, the graph B has positive y-values in the entire interval [-3, -2].

Therefore, the answer is Graph B    

 

Answer:

B

Step-by-step explanation: