Respuesta :
[tex]f(x) = \log_b(x)[/tex] is a decreasing function when [tex]0 < b < 1[/tex]
This is because we can use the change of base formula to say
[tex]\log_b(x) = \frac{\log(x)}{\log(b)}[/tex]
If b is between 0 and 1, not including either endpoint, notice how the log(b) term is negative.
For example, if b = 0.5, then log(b) = log(0.5) = -0.301 approximately. I'm using log base 10 to get log(0.5) = -0.301
So for b = 0.5, we have,
[tex]\log_{0.5}(x) = \frac{\log(x)}{\log(0.5)} \approx \frac{\log(x)}{-0.301} \approx -3.322\log(x)[/tex]
The log(x) part on its own is always increasing. The negative coefficient out front flips it to always decreasing.
By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex]decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D) #SPJ5
How to define the behavior of a logarithm
Logarithms are trascendent functions whose form is defined by the following expression:
[tex]\log _{b} x[/tex] such that [tex]x = b^{a}[/tex], where b > 0.
Where b is the base of the power.
Whose rules are described below:
- The logarithm is an increasing function if its base is less than 1.
- The logarithm is a decreasing function if its base is greater than 1.
By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex] is a decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D)
Remark
The statement is poorly formatted and reports several mistakes. Correct form is shown below:
For what values of b will [tex]F(x) = \log_{b} x[/tex] be a decreasing function?
A. b > 0
B. 0
C. b < 0
D. 0 < b < 1
To learn more on logarithms, we kindly invite to check this: https://brainly.com/question/20785664 #SPJ5
