The weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.
The given parameters:
- Weight of the satellite, F = 200 N
- One Earth radius above the surface of Earth = 2R
The gravitational force on the satellite is calculated by applying Newton's law of universal gravitation is calculated as;
[tex]F = \frac{Gm_1m_2}{R^2} \\\\F_1 R_1^2 = F_2R_2^2\\\\F_2 = \frac{F_1 R_1^2 }{R_2^2} \\\\F_2 =\frac{200 \times R_1^2}{(2R_1)^2} \\\\F_2 = \frac{200 \times R_1^2 }{4R_1} \\\\F_2 = 40 \ N[/tex]
Thus, the weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.
Learn more about Newton's law of universal gravitation here: https://brainly.com/question/9373839
