How many grams are in 36.2 moles of Iron (I) fluoride?
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Answer:
4084.808 grams (SigFigs: 4085 grams)
Explanation:
The molar mass of Iron fluoride is 112.84 g/mol.
To calculate the mass, multiply the molar mass by the number of moles.
36.2 mol * 112.84 g/mol = 4084.808 g
Convert to Sigfigs (if necessary):
4085 g