Answer:
the volume of the solid is 1024/3 cubic unit
Step-by-step explanation:
Given the data in the question,
radius of the circular disk = 4
Now if the center is at ( 0,0 ), the equation of the circle will be;
x² + y² = 4²
x² + y² = 16
we solve for y
y² = 16 - x²
y = ±√( 16 - x² )
{ positive is for the top while the negative is for the bottom position }
A = b²
b = 2√( 16 - x² ) { parallel cross section }
A = [2√( 16 - x² )]²
A = 4( 16 - x² )
Now,
VOLUME = [tex]\int\limits^r -rA dx[/tex]
= [tex]\int\limits^4_4 {-4(16-x^2)} \, dx[/tex]
= 4[ 16x - (x³)/3 ] { from -4 to 4 }
= 4[ ( 64 - 64/3 ) - (-64 = 64/3 0 ]
= 4[ 64 - 64/3 + 64 - 64/3 ]
= 4[ (192 - 64 + 192 - 64 ) / 3 ]
= 4[ 256 / 3 ]
= 1024/3 cubic unit
Therefore, the volume of the solid is 1024/3 cubic unit
