Answer:
100 mL
Explanation:
The reaction that takes place is:
- CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
First we convert 500 mg of CaCO₃ into mmoles, using its molar mass:
- 500 mg ÷ 100 mg/mmol = 5 mmol CaCO₃
Then we convert 5 mmoles of CaCO₃ into HCl mmoles, using the stoichiometric coefficients of the balanced reaction:
- 5 mmol CaCO₃ * [tex]\frac{2mmolHCl}{1mmolCaCO_3}[/tex] = 10 mmol HCl
Finally we calculate the volume of a 0.10 M HCl solution (such as stomach acid) that would contain 10 mmoles:
- 10 mmol / 0.10 M = 100 mL
