Answer:
[tex] 365.97\: cm^2[/tex]
Step-by-step explanation:
Area of the shape = Area of triangle with base 22 cm and height 16 cm + Area of semicircle with radius (22/2 = 11) 11 cm
[tex] = \frac{1}{2}bh + \frac{1}{2} \pi {r}^{2} \\ \\ = \frac{1}{2} \times 22 \times 16 + \frac{1}{2} \times \times 3.14 {(11)}^{2} \\ \\ = 11 \times 16 + 3.14 \times 60.5 \\ \\ = 176 + 189.97 \\ \\ = 365.97 \: {cm}^{2} [/tex]
The radius would be 11 which is half of the width and the height is 16.
A= πr(r+√h²+r²)
A= π•11•(11+√16²+11²)
A≈ 1051.11836
