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Consult the attached diagram.
In the larger triangle,
tan(16°) = (7250 ft) / (x + y)
and in the smaller triangle,
tan(26°) = (7250 ft) / y
You want to solve for x.
From the first equation (I'm ignoring units from here on, all distances are measured in ft), you have
(x + y) tan(16°) = 7250
x tan(16°) + y tan(16°) = 7250
x tan(16°) = 7250 - y tan(16°)
x = 7250 cot(16°) - y
From the second equation,
y = 7250 cot(26°)
Solving for x gives
x = 7250 cot(16°) - 7250 cot(26°)
x = 7250 (cot(16°) - cot(26°))
x ≈ 10,433 ft
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The distance the plane traveled from point A to point B is 10,433 ft.
We have given that,
Carter spots an airplane on the radar that is currently approaching in a straight line, and that will fly directly overhead.
The plane maintains a constant altitude of 7250 feet.
In the larger triangle,tan(16°) = (7250 ft) / (x + y)and in the smaller triangle,
What is the tan ratio?
[tex]tan(\ theta)=\frac{\\opposite \side }{hypotenouse}[/tex]tan(26°) = (7250 ft) / y
we have to solve for x.
From the first equation (I'm ignoring units from here on, all distances are measured in ft),
you have
(x + y) tan(16°) = 7250
x tan(16°) + y tan(16°) = 7250
x tan(16°) = 7250 - y tan(16°)
x = 7250 cot(16°) - y
From the second equation,
y = 7250 cot(26°)
Solving for x gives
x = 7250 cot(16°) - 7250 cot(26°)
x = 7250 (cot(16°) - cot(26°))x ≈ 10,433 ft
Therefore the distance the plane traveled from point A to point B is 10,433 ft.
To learn more about altitude visit:
https://brainly.com/question/22736499
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